Let's say the original intensity is denoted as I1, and the doubled intensity is denoted as I2.ĭ2 - d1 = 10 * log10(I2 * 12^12) - 10 * log10(I1 * 12^12) Therefore, the intensity of sound if the sound level of a pneumatic drill 10 meters away is 90 decibels is approximately 47.4 * 10^(-9) watts per square meter.Ĭ) To find how the value of d changes if the intensity is doubled, we calculate the difference between the values of d for the original intensity and the doubled intensity: Therefore, the number of decibels of sound produced by the jet engine at a distance of 50 meters with an intensity of 10 watts per square meter is approximately 131.6 decibels.ī) To find the intensity of sound if the sound level of a pneumatic drill 10 meters away is 90 decibels, we need to rearrange the formula and solve for I: Where d represents the number of decibels and I represents the intensity of sound in watts per square meter.Ī) To find the number of decibels of sound produced by a jet engine at a distance of 50 meters with an intensity of 10 watts per square meter, we substitute the given values into the formula: 1 answer To solve these problems, we will use the given formula for the decibel scale:
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |